Question

: x^ 3 +y^ 3 +z^ 3 -3xyz= 1 2 (x+y+z)[(x-y)^ 2 +(y-z)^ 2 +0 z-x)²]​

Answer 1

Answer:

please try this

Step-by-step explanation:

=(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx)

=

2

1

(x+y+z)(2x

2

+2y

2

+2z

2

−2xy−2yz−2zx)

=

2

1

[(x+y+z)(x−y)

2

+(y−z)

2

+(z−x)

2

]