Question

X^3+y^3+z^3=K if K=42

please answer and no wrong answers​

Answer 1

Given:-

K = 42

step-by-step explaination:-

=> x³ + y³ + z³ = k

[putting the value of K in given equation.]

=> x³ + y³ + z³ = 42

Taking ³ common from x , y and z.

=> (x + y + z)³ = 42

=> x + y + z = ³√42

=> x + y + z = 3.476

Hence, value of x , y and z is 3.476

Answer 2

If x,y,z can be real values (not just limited to integers), then there can be more than one solution possible, (consider permutations as well, for example, if x=a, y=b, z=c or (a,b,c) is a solution, then so are (c,a,b) (b,c,a) and other permutations.

if only integers are needed, then the solution set becomes smaller.

To reduce complexity let us consider only positive values of x,y,z are allowed, in that case any of x,y,z can not be greater than K^(1/3) so upper limit for k= 100 will be x,y,z<100^(1/3) or about <5.

we have only 4 integers less than 5 = 1,2,3,4

which leads to 4*4*4 = 64 combinations only so easily x,y,x can be calculated by executing a small program to evaluate x^3+y^3+z^3 in one of the computer programming languages (c, c++ etc) for any 1<= K <= 100

HOPE this helps you ☺️