Question

x/3+y/4=11,5x/6-y/3+7=0

Answer 1

x/3+y/4=11
multiplying by 12, then
4x+3y =132.......(1)
5x/6-y/3+7 =0
5x/6-y/3= -7
multiplying by 18, then
15x-6y= -126........(2)
in equation (1) multiplying by 2, then, 8x+6y =264........(3)
(2)+(3)
we get, 23x =138
ie, x= 138/23= 6
ie, x=6
put the value of x into equation (1), we get,
24+3y=132
3y =108
y =36
we get the values are x=6 and
y = 36

Answer 2

Answer:

Step-by-step explanation:

multiplying by 12, then

4x+3y =132.......(1)

5x\/6-y\/3+7 =0

5x\/6-y\/3= -7

multiplying by 18, then

15x-6y= -126........(2)

in equation (1) multiplying by 2, then, 8x+6y =264........(3)

(2)+(3)

we get, 23x =138

ie, x= 138\/23= 6

ie, x=6

put the value of x into equation (1), we get,

24+3y=132

3y =108

y =36

we get the values are x=6 and