Question

x/3+y/4=11 , 5x/6-y/3+7=0 by substitution methods​

Answer 1

Step-by-step explanation:

The given system of equations is Let us eliminate y from the given equations. The coefficients of y in the equations(iii) and (iv) are 3 and 2 respectively. The L.C.M of 3 and 2 is 6. So, we make the coefficient of y equal to 6 in the two equations. Hence, the solution of the given system of equations is x=6, y=36Read more on Sarthaks.com - https://www.sarthaks.com/29433/solve-the-following-systems-of-equations-x-3-y-4-11-5x-6-y-3-7