Math, asked by kajay03993, 9 months ago

x/3+y/4=11
5x/6-y/3=-7​

Answers

Answered by rathod9999
1

Answer:

1] x/3 + y/4 = 11

[2] 5x/6 - y/3 = -7

// To remove fractions, multiply equations by their respective LCD

Multiply equation [1] by 12

Multiply equation [2] by 6

// Equations now take the shape:

[1] 4x + 3y = 132

[2] 5x - 2y = -42

Graphic Representation of the Equations :

3y + 4x = 132 -2y + 5x = -42

Solve by Substitution :

// Solve equation [2] for the variable x

[2] 5x = 2y - 42

[2] x = 2y/5 - 42/5

// Plug this in for variable x in equation [1]

[1] 4•(2y/5-42/5) + 3y = 132

[1] 23y/5 = 828/5

[1] 23y = 828

// Solve equation [1] for the variable y

[1] 23y = 828

[1] y = 36

// By now we know this much :

x = 2y/5-42/5

y = 36

// Use the y value to solve for x

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