x/3+y/4=11 ,5x/6+y/3=-7 solve by elimination mathod
mainagar2:
love her
ya i love her
❤❤❤muskan❤❤❤
i love you
:)
bye
bye
good night didi
you are really lucky
naam se bhi aur baki sab se
Answers
Answered by
4
x/3 + y/4 = 11
=> 4x +3y= 132 ----------(1)
5x/6 + y/3 =-7
=> 5x+ 2y= - 42 -----------(2)
multiplying by 2 in eq(1) and by 3 in eq( 2)
8x + 6y = 264
15x + 6y = - 126
-----------------------
-7x = 390
x = - 390/7
putting above value in eq (1)
4 (-390/7) +3 y =132
-1560/7 +3y =132
3y= 2584/7
y = 828/7
☆☆ :)
=> 4x +3y= 132 ----------(1)
5x/6 + y/3 =-7
=> 5x+ 2y= - 42 -----------(2)
multiplying by 2 in eq(1) and by 3 in eq( 2)
8x + 6y = 264
15x + 6y = - 126
-----------------------
-7x = 390
x = - 390/7
putting above value in eq (1)
4 (-390/7) +3 y =132
-1560/7 +3y =132
3y= 2584/7
y = 828/7
☆☆ :)
Similar questions