x/3+y/4=4; x/2-y/4=1 Solve the given simultaneous equation...answer fast it's urgent
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Given that,
x/3 + y/4 = 4 ...(i)
x/2 - y/4 = 1 ...(ii)
Now, adding (i) and (ii), we get
x/3 + x/2 = 4 + 1
or, 5x/6 = 5
or, x = 6
Now, putting x = 6 in (i), we get
6/3 + y/4 = 4
or, y/4 = 4 - 2
or, y/4 = 2
or, y = 8
Therefore, the required solution be
x = 6, y = 8
Hope it helps! (:
Given that,
x/3 + y/4 = 4 ...(i)
x/2 - y/4 = 1 ...(ii)
Now, adding (i) and (ii), we get
x/3 + x/2 = 4 + 1
or, 5x/6 = 5
or, x = 6
Now, putting x = 6 in (i), we get
6/3 + y/4 = 4
or, y/4 = 4 - 2
or, y/4 = 2
or, y = 8
Therefore, the required solution be
x = 6, y = 8
Hope it helps! (:
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