Question

x/3+y/4=5 x/2+y/3=7 by substitution method​

Answer 1

Answer:

x=6 and y=12

Step-by-step explanation:

x/3 + y/4 = 5            -------- Equation 1

x/2 + y/3 = 7            -------- Equation 2

From Equation 1 we get ,

x/3 + y/4 = 5

LCM of 3 and 4 is 12

4x+3y/12 = 5

4x + 3y = 12 x 5 = 60

Therefore , 4x + 3y = 60   --------- Equation 3

From Equation 2 we get ,

x/2+y/3=7

LCM of 2 and 3 is 6

3x+2y/6 = 7

3x + 2y = 7 x 6 = 42

Therefore , 3x + 2y = 42   --------- Equation 4

From Equation 3,

4x + 3y = 60

x = 60 - 3y /4

Substituting x in Equation 4 , we get

3(60-3y/4) + 2y = 42

45 - 9y/4 + 2y = 42

9y/4 - 2y = 45-42

9y-8y/4 = 3

y/4 = 3

y = 12

Substituting y in Equation 3 , we get

4x + 3y = 60

4x + 3 x 12 = 60

4x + 36 = 60

4x = 60-36 = 24

x = 24/4 = 6

x = 6

Therefore , x=6 and y=12

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