x/3+y/5=1 and 7x-5y=21 solve this by substitution method
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Step-by-step explanation:
We have,
x/3+y/5=1=> X/3=y-5/y
x=3(y-5/y)
now my dear friend, put it in other equation
7(3(y-5/y))-5y=21
21(y-5/y)-5y=21
and now quadratic equation in y will come, find y and the by putting it in any eqn find x
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