Question

x/3+y/5=1 solve by elemination

Answer 1

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

x/3+y/5=1 solve by elemination

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

------>>>>Here is your answer<<<<--------

$➭ \frac{x}{3} + \frac{y}{5} = 1$

$➭ \frac{5x + 3y}{15} = 1$

$➭5x + 3y = 15$

$➭x = \frac{15 - 3y}{5}$

➭put the value of x in another equation to find the value of y..

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

Answer:

x = 0 and y = 5 .

Step-by-step explanation:

x/3 + y/5 =1 ...eq(1)

5x+3y /15 = 1

5x+3y = 15

x = 15 - 3y / 5 ... eq(2)

Substituting eq(2) in eq(1)

15-3y/5 + y/5 = 1

15-3y+y / 5 = 1

15 - 2y = 5

-2y = 5 - 15

y = -10/-2

y= 5 .

therefore , x = 15 - 3y / 5 = 15 - 3(5)/5 = 15 -15 /5 = 0 .

Therefore , x = 0 and y = 5 .

Hope this helps .

Have a nice day ahead !