{x/3+y/5}^(3)-{x/3-y/5}^(3)
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Hi ,
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we know that ,
( a + b )³ - ( a - b )³
= a³+3a²b+3ab²+b³ - ( a³ -3a²b + 3ab² - b³ )
= 6a²b + 2b³
********************************
Here ,
a = x/3 , b = y/5
( x/3 + y/5 )³ - ( x/3 - y/5 )³
= 6 × ( x/3 )² ( y/5 ) + 2 × ( y/5 )³
= 6x²y/45 + 2y³/125
= ( 2x²y/15 ) + 2y³/125
I hope this helps you.
: )
***********************
we know that ,
( a + b )³ - ( a - b )³
= a³+3a²b+3ab²+b³ - ( a³ -3a²b + 3ab² - b³ )
= 6a²b + 2b³
********************************
Here ,
a = x/3 , b = y/5
( x/3 + y/5 )³ - ( x/3 - y/5 )³
= 6 × ( x/3 )² ( y/5 ) + 2 × ( y/5 )³
= 6x²y/45 + 2y³/125
= ( 2x²y/15 ) + 2y³/125
I hope this helps you.
: )
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