Math, asked by sonalchordiya8055, 5 hours ago

x/3+y=7/3;2x-y/3=23/3solve in elimination method​

Answers

Answered by sabeshinimohanbts200
1

Answer:

x=2

y=1

Step-by-step explanation:

x/3+y=7/3 ----------→ equation 1

2x-y/3=23/3 --------→ equation 2

Multiply equation 1 by 6

6.x/3 + 6.y = 6. 7/3

2x +6y = 14 ----------→ equation 3

Subtract equation 3 and 2

2x +6y = 14

2x-y/3=23/3

(-) (+) (-)

___________

6y+(y/3) = -23/3 +14

(18y+y/3 )= -23+42/3

( cancel '3' from both side of the equation).

19y = 19

y=1

substitute y=1 in equation 3

2x+6(1)=14

2x= 8

x=8/4

x=2

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