x/3+y=7/3;2x-y/3=23/3solve in elimination method
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Answer:
x=2
y=1
Step-by-step explanation:
x/3+y=7/3 ----------→ equation 1
2x-y/3=23/3 --------→ equation 2
Multiply equation 1 by 6
6.x/3 + 6.y = 6. 7/3
2x +6y = 14 ----------→ equation 3
Subtract equation 3 and 2
2x +6y = 14
2x-y/3=23/3
(-) (+) (-)
___________
6y+(y/3) = -23/3 +14
(18y+y/3 )= -23+42/3
( cancel '3' from both side of the equation).
19y = 19
y=1
substitute y=1 in equation 3
2x+6(1)=14
2x= 8
x=8/4
x=2
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