Question

(x+30)(540/x -3)=540 solve the following quadratic equation by factorization method ​

Answer 1

$\underline{\textbf{Given:}}$

$\mathsf{(x+30)\left(\dfrac{540}{x}-3\right)=540}$

$\underline{\textbf{To find:}}$

$\textsf{The roots of the given quadratic equation}$

$\underline{\textbf{Solution:}}$

$\mathsf{Consider,}$

$\mathsf{(x+30)\left(\dfrac{540}{x}-3\right)=540}$

$\mathsf{(x+30)\left(\dfrac{540-3x}{x}\right)=540}$

$\mathsf{(x+30)(540-3x)=540x}$

$\mathsf{540x-3x^2+16200-90x=540x}$

$\mathsf{-3x^2+16200-90x=0}$

$\mathsf{3x^2-16200+90x=0}$

$\mathsf{3x^2+90x-16200=0}$

$\mathsf{x^2+30x-5400=0}$

$\mathsf{x^2+90x-60x-5400=0}$

$\mathsf{x(x+90)-60(x+90)=0}$

$\mathsf{(x-60)(x+90)=0}$

$\impies\mathsf{x-60=0\;\;(or)\;\;x+90=0}$

$\impies\mathsf{x=60\;\;(or)\;\;x=-90}$

$\therefore\textsf{The roots of the given equation are 60, -90}$

$\underline{\textbf{Find more:}}$

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Answer 2

Answer:

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