ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ᴇxᴩʟᴀɴᴀᴛɪᴏɴ ɴᴇᴇᴅᴇᴅ .......
ᴡᴀʀɴɪɴɢ:-ꜱᴩᴀᴍᴍᴇʀꜱ ʙᴇ ᴀᴡᴀʀᴇ ᴏꜰ ᴍᴇ
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AB = AC = a
AD = b
AD perpendicular to BC (BC is tangent for smaller circle)
BD = DC (A perpendicular drawn from the centre of a circle to a chord, bisects the chord)
BC = BD + DC
BC = BD + BD
BC = 2BD
In ∆ADB,
by using pythegorus theorem
H² = B² + P²
AB² = BD² + AD²
a² = BD² + b²
BD² = a² - b²
BC = 2BD
BC = 2√a²- b²
Answer : (d) 2 √a²-b²
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