Question

(x^32+1/x^32)(x^8+1/x^8)(x-1/x)(x^16+1/x^16)(x+1/x)(x^4+1/x^4) सरलीकृत मान क्या है?( 1) x^64+1/x^64 (2) x^64- 1/x^64/x^2+1/x^2 (3) x^64-1/x^64/x+1/x (4) x^32-1/x^32/x+1/x​

Answer 1

Answer:

(64)*/* (?) - (64) X 4 (a) 1 (b) 2 1 1 (C) 2 (d) 16 हल (a) –2 (64)*/* × (4) - (43)2/3 × (4*)* = 4* × 4* = 4" = 1 14. (256)"" (256)""” का ... (4*)*/4 = 4 15. ( 8 )” को सरलीकृत ... x दोनों पक्षों का वर्ग करने पर 1 + AI1 +५/1 +२/T +. . . . = x* => x + 1 ...

Answer 2

Answer:

Ups it is to confusing Yr.........