Question

ᴡʜᴀᴛ ɪꜱ ᴍᴏᴍᴇɴᴛ ᴏꜰ ɪɴᴇʀᴛɪᴀ ᴏꜰ ᴀ ᴅɪꜱᴄ ᴏꜰ ᴍᴀꜱꜱ ᴍ ᴀɴᴅʀᴀᴅᴜᴜꜱ ʀ ᴀʙᴏᴜᴛᴀɴ ᴀxɪꜱ ᴩᴀꜱꜱɪɴɢ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴄᴇɴᴛᴇʀ ᴏᴅ ꜰ ᴩᴀʀᴀʟᴇʟ ᴛᴏ ᴛʜᴇ ᴩʟᴀɴᴇ​

Answer 1

Answer:

movement of inertia of disc about its diameter is Id = 1/2 MR2

MI of disc about a tangent passing through rim and in the plane of disc is

I=IG+ MR2 = 1/4 MR2 +MR2= 5/4 MR2.

Answer 2

Explanation:

The moment of inertia of a disc of mass M and radius R about an axis. Which is tangential to sircumference of disc and parallel to its diameter is. Solution : (a) I=Icm=Mh2+(14)MR2+MR2=(54)MR2.