Question

x=3a-7b+2c,y=5a+2b-7c,z=-a+4b-5c find the value of x+y-z in terms of a,b,c​

Answer 1

Given

• x= 3a-7b+2c
• y= 5a+2b-7c
• z= (-a+4b-5c)

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Need to Find:

• x+y-z=?, in terms of a,b,c

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$\huge{\underline{\underline{\red{Solution}}}}$

x+y-z

=(3a-7b+2c)+(5a+2b-7c)-(-a+4b-5c)

=3a-7b+2c+5a+2b-7c+a-4b+5c

=(3a+5a+a)+(-7b+2b-4b)+ (2c-7c+5c)

=9a-9b+0c

=9a-9b+0c

or

=9(a-b)

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$\red{\boxed{\boxed{Answer=\:9(a-b)\:or\:9(a-b)+0c}}}$

Answer 2

Answer:

Step-by-step explanation:

Keeping the value of x , y, z :-

(3a - 7b + 2c) + (5a +2b -7c) - (a + 4b - 5c)

=3a - 7b + 2c +5a + 2b - 7c - a - 4b + 5c

=3a + 5a - a - 7b + 2b - 4b + 2c -7c + 5c

=8a - a -11b + 2b + 7c - 7c

= 7a - 9b