(X^3cosx/2-1/2)((4-x^2)dx))^1/2
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Split the integrand in two items:
F = 1/2 Sqrt[4 - x^2] + x^3 Cos[x/2] Sqrt [4-x^2]
The second item is an odd function, and its integral within [-2, +2] is zero.
Sqrt [4-x^2] is a half-circle with center at the origin and radius 2. The area of the half-circle is 2 Pi, so Integral [F] = Pi
Step-by-step explanation:
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