Math, asked by homie31141, 1 year ago

x=3sec theta y=4tan theta

Answers

Answered by Devendra95
0

Step-by-step explanation:

x=3sec theta

y=4tan theta

now sec theta=x/3

tan theta=y/4

sec^2 theta-tan^2 theta=x^2/9-y^2/16

1=x^2/9-y^2/16

(sev^2theta-tan^2theta)=1

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