Question

x=3sin teta,y=4cos teta find root of 16x²+9y²​

Answer 1

Answer:

12

Step-by-step explanation:

16x^2= 16x3x3sin^2theta =144sin^2theta            eq 1

9y^2 = 9x4x4cos^2theta           eq2

1+2=root 144(sin^2theta+cos^2theta)

      root 144(1)

       12

Answer 2

Answer:

Answer=144

x=3sin theta

y=4cos theta

16xpower2+9ypower

16(3sintheta )power2 + 9(4costheta )power2

16(9sinpower2theta)+9(16cospower2theta)

144(sinpower2theta + cospower2theta)

144