Question

X=3sint -sin3t
Y=3cost -cos3t
Find dy/dx ,t=π/3

Answer 1

Derivative dx/dt=3cost-3cos3t and dy/dt=-3sint+3sin3t, and divide 1 & 2 eq.we get dy /dx =-3(root3/2)+3(0)/3(1/2)-3(-1)=root3/3

Answer 2

Subordinate dx/dt=3cost-3cos3t and dy/dt=-3sint+3sin3t, and partition 1 and 2 eq. We get dy/dx =-3 (root3/2) + 3(0)/3(1/2) – 3 (- 1) = root3/3.

These will turn into the points of confinement of reconciliation for the line essential over dt.

With a little examination, we can distinguish the beginning and halting qualities for the parameter.