x=3t2-4t+6 find initial velocity
Answers
Answered by
2
Answer:
Given distance-time relation
x
=
(
t
2
−
4
t
+
6
)
Velocity
v
=
d
x
d
t
=
2
t
−
4
Acceleration
a
=
d
v
d
t
=
2
m
s
−
2
Velocity at
t
=
0
v
0
=
−
4
m
s
−
1
Similar questions