Question

x=3t2+4t+6, then find velocity when t=4 second's​

Answer 1

Answer:

x=t

2

−4t+6

So, the change in velocity is:

dt

dx

=2t−4

Since velocity is changing,

At t=0,x

1

=6

At t=2,x

2

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x

3

=3

So distance traveled from t=2s to t=3s

x

3

−x

2

=3−2=1m

Thus the total distance is:

4+1=5m

Answer 2

Answer:

70 is the answer

Explanation:

x=3(4)²+4×4+6

x=3×16+16+6

x=48+22

x=70

I hope it's helpful for you