Question

-x^+3x+10=0 equations ​

Answer 1

Answer:

Step-by-step explanation:

 

3x%2B5y=-10 Subtract 10 from both sides

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

3x%2B5y=-10 Start with the given equation

3x%2B5y-3x=-10-3x Subtract 3x from both sides

5y=-3x-10 Simplify

%285y%29%2F%285%29=%28-3x-10%29%2F%285%29 Divide both sides by 5 to isolate y

y+=+%28-3x%29%2F%285%29%2B%28-10%29%2F%285%29 Break up the fraction on the right hand side

y+=+%28-3%2F5%29x-2 Reduce and simplify

The original equation 3x%2B5y=-10 (standard form) is equivalent to y+=+%28-3%2F5%29x-2 (slope-intercept form)

The equation y+=+%28-3%2F5%29x-2 is in the form y=mx%2Bb where m=-3%2F5 is the slope and b=-2 is the y intercept.

Answer 2

Answer: -2,5

Step-by-step explanation:

-x² + 3x + 10 = 0

=> -x² + 5x - 2x + 10 = 0

=> -x(x - 5) -2(x - 5) = 0

=> (-x - 2)(x - 5) = 0

=> -(x + 2)(x - 5) = 0

=> (x + 2)(x - 5) = 0

If (x + 2) = 0

Then, x = -2 .

If (x - 5) = 0

Then, x = 5 .

So the roots of the equation are -2,5

Hope this helps you .

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