Question

x-√3x-6=2 find the roots​

Answer 1

Step-by-step explanation:

${x}^{2} - \sqrt{3} x - 6 - 2 = 0 \\ {x}^{2} - \sqrt{3} x - 8 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - ( - \sqrt{3})± \sqrt{ {( - \sqrt{3} )}^{2} - 4 \times 1 \times ( - 8)} }{2 \times 4} \\ = \frac{ \sqrt{3}± \sqrt{3 + 32} }{2} \\ = \frac{ \sqrt{3} ± \sqrt{35} }{2}$