Question

(x) = 3x4 + 5x3 – 7x2 + 2x + 2 g(x) = x2 + 3x + 1 By division algorithm

Answer 1

Step-by-step explanation:

The energy initially stored by the capacitor is 1/2 C*V^2 or Q^2 / 2*C

When the plate separation is doubled, the charge remains constant and the capacitance is halved. The work done in separating the plates is the difference in energy stored: this is

Q^2 / 2*0.5*C - Q^2 / 2*C This represents double the initial energy less the initial energy. The work done in adding this energy is Q^2 / 2*C

Assigning values: ( 2*10–4 )^2 / ( 2* 10 *10^-6 ) = 2 mJ