x+3y=0 , 2x-3y=12 ..Solve it in substitution method. Ans step by step.
Answers
Answer:
x+3y=0
x= -3y (1)
2x-3y= 12 (2)
Substituting (1) in (2)
-6y-3y= 12
⇒y=-12/9= -4/3
substituting y= -4/3 in (1)
x+3×-4/3=0
x-4=0
⇒x=4
hence, x=4 y=-4/3
Step-by-step explanation:
Step-by-step explanation:
Yes, you can solve the given system of two simultaneous equations by the substitution method as follows:
For the given system of two simultaneous linear equations in two variables x and y, we’ll arbitrarily choose the first equation and then solve for y in terms of x (we could have chosen to solve for x in terms of y):
2x + y = 0
2x + (‒2x) + y = 0 + (‒2x)
y = ‒2x
Now, substitute this expression for y into the other equation and then solve for x as follows:
x ‒ 3y = 0
x ‒ 3(‒2x) = 0
x + 6x = 0
7x = 0
(1/7)(7x) = (1/7)(0)
x = 0
Now, substituting this value for x into the equation y = ‒2x and solve for y as follows:
y = ‒2x
y = ‒2(0)
y = 0
Check (very important):
NOTE: In order for x = 0 and y = 0 to be the solution to the given system of simultaneous equations, they must satisfy (make true) both equations.
2x + y = 0 and x ‒ 3y = 0
2(0) + 0 = 0 0 ‒ 3(0) = 0
0 + 0 = 0 0 ‒ 0 = 0
0 = 0 0 = 0
Therefore, the solution set for the given system is {(0, 0)}.