Question

x+3y=0 , 2x-3y=12 ..Solve it in substitution method. Ans step by step.​

Answer 1

Answer:

x+3y=0

x= -3y         (1)

2x-3y= 12   (2)

Substituting (1) in (2)

-6y-3y= 12

⇒y=-12/9= -4/3

substituting y= -4/3 in (1)

x+3×-4/3=0

x-4=0

⇒x=4

hence, x=4  y=-4/3

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Yes, you can solve the given system of two simultaneous equations by the substitution method as follows:

For the given system of two simultaneous linear equations in two variables x and y, we’ll arbitrarily choose the first equation and then solve for y in terms of x (we could have chosen to solve for x in terms of y):

2x + y = 0

2x + (‒2x) + y = 0 + (‒2x)

y = ‒2x

Now, substitute this expression for y into the other equation and then solve for x as follows:

x ‒ 3y = 0

x ‒ 3(‒2x) = 0

x + 6x = 0

7x = 0

(1/7)(7x) = (1/7)(0)

x = 0

Now, substituting this value for x into the equation y = ‒2x and solve for y as follows:

y = ‒2x

y = ‒2(0)

y = 0

Check (very important):

NOTE: In order for x = 0 and y = 0 to be the solution to the given system of simultaneous equations, they must satisfy (make true) both equations.

2x + y = 0 and x ‒ 3y = 0

2(0) + 0 = 0 0 ‒ 3(0) = 0

0 + 0 = 0 0 ‒ 0 = 0

0 = 0 0 = 0

Therefore, the solution set for the given system is {(0, 0)}.