Question

x-3y-0; 3x-15=0 solve using
Cross multiplication method​

Answer 1

Step-by-step explanation:

$x = 4 and y = 1</p><p></p><p>Step-by-step explanation:</p><p></p><p>Given : \begin{lgathered}x-3y-7=0 \\3x-3y-15=0\end{lgathered}x−3y−7=03x−3y−15=0</p><p></p><p>To Find :  solve it by cross multiplication method</p><p></p><p>Solution:</p><p></p><p>Cross multiplication method</p><p></p><p>Equations : \begin{lgathered}a_1x+b_1x+c_1=0\\a_2x+b_2x+c_2=0\end{lgathered}a1x+b1x+c1=0a2x+b2x+c2=0</p><p></p><p>\frac{x}{b_1c_2-c_1b_2}=\frac{y}{a_1c_2-a_2c_1} =\frac{1}{a_1b_2-a_2b_1}b1c2−c1b2x=a1c2−a2c1y=a1b2−a2b11</p><p></p><p>Comparing the given equations</p><p></p><p>\begin{lgathered}x-3y-7=0 \\3x-3y-15=0\end{lgathered}x−3y−7=03x−3y−15=0</p><p></p><p>\frac{x}{(-3)(-15)-(-7)(-3)}=\frac{y}{(1)(-15)-(3)(-7)} =\frac{1}{(1)(-3)-(3)(-3)}(−3)(−15)−(−7)(−3)x=(1)(−15)−(3)(−7)y=(1)(−3)−(3)(−3)1</p><p></p><p>\frac{x}{24}=\frac{y}{6} =\frac{1}{6}24x=6y=61</p><p></p><p>\frac{x}{4}=\frac{y}{1} =\frac{1}{1}4x=1y=11</p><p></p><p>So, x = 4 and y = 1</p><p></p><p>$

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Answer 2

Step-by-step explanation:

this is absolutely right