Question

X+3y+1=0,7x-2y+5=0 by elimination method

Answer 1

•Given:-

→x+3y+1=0

→x+3y=-1–-(1)

→7x-2y+5=0

→7x-2y=-5–-(2)

$\rule{200}{1}$

♪To Find:-

The value of x & y?

$\rule{200}{1}$

★Answer:-

♦Multiply eq-(1) by 2 and Multiply Eq-(2) by 3♦

→2x+6y=-2–-(3)

→21x-6y=-15–-(4)

♦Add Eq-(3)&(4)♦

•Check Attachment for Addition•

→x=$\frac{-17}{23}$–-(5)

♦Using (5) in any of the equation♦

[°Using-(5) in eq-(3)°–>i prefer]

→2×$\frac{-17}{23}$+6y=-2

→2×-17+6y=-2×23

→-34+6y=-46

→6y=-46+34

→6y=-12

→y=$\frac{\cancel{-12}}{\cancel{6}}$

→y=-2

$\rule{200}{1}$

x=$\frac{-17}{23}$

y=-2

$\rule{200}{8}$