x-3y=-1=2x-4y=2 how do you find the question
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Let's solve your system by substitution.
x−3y=−1;2x−4y=2
Step: Solvex−3y=−1for x:
x−3y=−1
x−3y+3y=−1+3y(Add 3y to both sides)
x=3y−1
Step: Substitute3y−1forxin2x−4y=2:
2x−4y=2
2(3y−1)−4y=2
2y−2=2(Simplify both sides of the equation)
2y−2+2=2+2(Add 2 to both sides)
2y=4
2y
2
=
4
2
(Divide both sides by 2)
y=2
Step: Substitute2foryinx=3y−1:
x=3y−1
x=(3)(2)−1
x=5(Simplify both sides of the equation)
Answer:
x=5 and y=2
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