Question

x-3y=1 ,3x-2y+4=0 simutaneously

Answer 1

Hey!!!....Here is ur answer

x-3y=1 ---- eq1

3x-2y= -4 ----eq2

multiply by 3 in eq1 and subtracting from eq2

-y=5

y= -5

put the value of y in eq 1

x-3 (-5)=1

x+15=1

x= -14

So x= -14 and y= -5

Hope it will help you

Answer 2

Concept

Whatever you do to one side of the equation, you must also do to the other side. As a result, if you add or subtract to make a variable on one side of the equation disappear, you also need to do so on the other. By merging like terms, the equation can be made simpler.

Given

x ₋ 3y = 1 ......... eq(1)

3x ₋ 2y ₊4 = 0 ......... eq(2)

Find

we are asked to solve the equation and find the values of x and y.

Solution

x ₋ 3y = 1 ......... eq(1)

3x ₋ 2y ₊4 = 0 ......... eq(2)

Now multiply the equations with the opposit first number of there respective equation.

3(x ₋ 3y = 1) ....... eq(1)

1(3x ₋ 2y ₊4 = 0) ......... eq(2)

we get the required equations as

3x ₋3y = 3 ........ eq(1)

3x ₋ 2y = ₋4 ........ eq(2)

Now solve both the equations.

3x ₋3y = 3 ........ eq(1)

3x ₋ 2y = ₋4 ........ eq(2)

⁻     ⁺        ⁺

like terms of x gets cancelled.

hence we get ₋y = 7 ⇒ y = ₋7

now substitute y value in eq (2) to get the value for x.

3x ₋ 2y = ₋4 ........ eq(2)

3x ₋ 2(₋7) = ₋4

3x ₊ 14 = ₋4

3x = ₋4 ₋14

3x = ₋18

x = -6

Therefore we get the values of x and y as ₋7 and ₋9 respectively.

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