x+3y=10 2x+3y=21 solve using the elimination method
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Answer:
x = 11 and y = -1/3
Step-by-step explanation:
The given equations are :
x + 3y = 10 ...(1)
2x + 3y = 21 ...(2)
From equation (1), we get;
x + 3y = 10
x = 10 - 3y
Substituting x = 10 - 3y in equation (2), we get;
2x + 3y = 21
2 (10 - 3y) + 3y = 21
20 - 6y + 3y = 21
20 - 3y = 21
-3y = 21 - 20
-3y = 1
y = 1/-3
y = -1/3
Substituting the value of y in equation (1), we get;
x + 3y = 10
x + 3 (-1/3) = 10
x - 3/3 = 10
(3x - 3)/3 = 10
3x - 3 = 10 x 3
3x - 3 = 30
3x = 30 + 3
3x = 33
x = 33/3
x = 11
Hope it helps u...
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