Question

(x + 3y + 12z) (12yz + 4zx + xy) - 12xyz​

Answer 1

Answer:

We write 9x2 + 12xy = (3x)(3x) + (3x)(4y)

Here 3x is the common to both the terms. Hence,

(3x)(3x) + (3x)(4y) = 3x(3x + 4y)

Thus, 3, x, (3x + 4y) are the factors of 9x2 + 12xy