x+3y=15 and 2x-3y=-6 find the coordinates with solutions
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The two lines are
x + 3y = 15 ...(i)
2x - 3y = - 6 ...(ii)
Now, adding (i) and (ii) no. equations, we get
x + 3y + 2x - 3y = 15 - 6
or, 3x = 9
or, x = 9/3
or, x = 3
Now, putting x = 3 in (i), we get
3 + 3y = 15
or, 3y = 15 - 3
or, 3y = 12
or, y = 12/3
or, y = 4
Therefore, the required point of intersection of the two lines are (3, 4).
____________________
NOW, to draw a graph :-
The first line is
x + 3y = 15
or, x/15 + 3y/15 = 1
or, x/15 + y/5 = 1
So, we have two points (15, 0) and (0, 5) to draw the first line.
The second line is
2x - 3y = - 6
or, 2x/(-6) - 3y/(-6) = 1
or, x/(-3) + y/2 = 1
So, we have two points (-3, 0) and (0, 2) to draw the second line.
[N.B. - To draw the 1st line, you can take two points (3, 4) and (0, 5)]
___________________
#MarkAsBrainliest
The two lines are
x + 3y = 15 ...(i)
2x - 3y = - 6 ...(ii)
Now, adding (i) and (ii) no. equations, we get
x + 3y + 2x - 3y = 15 - 6
or, 3x = 9
or, x = 9/3
or, x = 3
Now, putting x = 3 in (i), we get
3 + 3y = 15
or, 3y = 15 - 3
or, 3y = 12
or, y = 12/3
or, y = 4
Therefore, the required point of intersection of the two lines are (3, 4).
____________________
NOW, to draw a graph :-
The first line is
x + 3y = 15
or, x/15 + 3y/15 = 1
or, x/15 + y/5 = 1
So, we have two points (15, 0) and (0, 5) to draw the first line.
The second line is
2x - 3y = - 6
or, 2x/(-6) - 3y/(-6) = 1
or, x/(-3) + y/2 = 1
So, we have two points (-3, 0) and (0, 2) to draw the second line.
[N.B. - To draw the 1st line, you can take two points (3, 4) and (0, 5)]
___________________
#MarkAsBrainliest
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