Math, asked by shravan7115, 3 months ago

X-3y=16,2x-y=4 by elimination method

Answers

Answered by vivekbt42kvboy
2

Answer:

Use elimination to solve:

L1 x+3y=16

L2 2x-y=4

Multiply L2 by 3 so that when you add L1+L2 the y's cancel so that you can solve for x.

L2 3(2x-y)=3(4) ---> 6x-3y=12

Now add this to L1:

x+3y=16

6x-3y=12

_________

7x+0=28

7x=28

7x/7=28/7

x=4

Now substitute 4 in for x in either L1 or L2 and solve for y, I'm going with L1:

(4)+3y=16

4+3y=16

4-4+3y=16-4

3y=12

3y/3=12/3

y=4

The solution (x,y) is (4,4)

Happy Calculating!!!

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