X-3y=16,2x-y=4 by elimination method
Answers
Answered by
2
Answer:
Use elimination to solve:
L1 x+3y=16
L2 2x-y=4
Multiply L2 by 3 so that when you add L1+L2 the y's cancel so that you can solve for x.
L2 3(2x-y)=3(4) ---> 6x-3y=12
Now add this to L1:
x+3y=16
6x-3y=12
_________
7x+0=28
7x=28
7x/7=28/7
x=4
Now substitute 4 in for x in either L1 or L2 and solve for y, I'm going with L1:
(4)+3y=16
4+3y=16
4-4+3y=16-4
3y=12
3y/3=12/3
y=4
The solution (x,y) is (4,4)
Happy Calculating!!!
Similar questions
Business Studies,
1 month ago
Computer Science,
1 month ago
Math,
1 month ago
Chemistry,
3 months ago
Chemistry,
3 months ago
Math,
9 months ago
Computer Science,
9 months ago