Question

x+3y=16,2x-y=4 solve in elimination method plz

Answer 1

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Answer 2

Answer:

The value of x=4 and y=4.  

Step-by-step explanation:

Given : Equations $x+3y=16$ and $2x-y=4$

To find : Solve the equations by elimination method?

Solution :

$x+3y=16$ .....(1)

$2x-y=4$ .....(2)

To eliminate y multiply the equation (2) by 3 and Add in (1)

Multiply by 3 $6x-3y=12$

Add in (1) $x+3y+6x-3y=16+12$

$7x=28$

$x=\frac{28}{7}$

$x=4$

Substitute the value of x in (1),

$4+3y=16$

$3y=16-4$

$3y=12$

$y=\frac{12}{3}$

$y=4$

Therefore, The value of x=4 and y=4.