Πx+3y=25, write y in terms of x and also find the two solutions of this equation
Answers
Answered by
78
Hi ,
i ) pi ×x + 3 y = 25
3y = 25 - pi× x
y = ( 25 - pi × x )/ 3
y = 25/3 - pi × x /3
ii )
If x = 7
y = 25/ 3 - ( 22/ 7 )× ( 7/3)
y = 25/3 - 22 /3
y = ( 25 - 22 )/3
y = 3/3
y = 1
ii) if x = - 7
y = 25/3 - ( 22/ 7 ) × ( - 7 / 3 )
y = 25/ 3 + 22 / 3
y = ( 25 + 22 )/ 3
y = 47/ 3
Two solutions are
( 7 , 1 ) , ( -7 , 47 / 3 )
I hope this helps you.
****
i ) pi ×x + 3 y = 25
3y = 25 - pi× x
y = ( 25 - pi × x )/ 3
y = 25/3 - pi × x /3
ii )
If x = 7
y = 25/ 3 - ( 22/ 7 )× ( 7/3)
y = 25/3 - 22 /3
y = ( 25 - 22 )/3
y = 3/3
y = 1
ii) if x = - 7
y = 25/3 - ( 22/ 7 ) × ( - 7 / 3 )
y = 25/ 3 + 22 / 3
y = ( 25 + 22 )/ 3
y = 47/ 3
Two solutions are
( 7 , 1 ) , ( -7 , 47 / 3 )
I hope this helps you.
****
Answered by
4
Answer:
πx+3y=25
Step-by-step explanation:
y = (25-π×x)/3
y = 25/3-π×x/3
if x=7
y = 25/3- (22)/3
y = 25/3-22/3
y = (25-22)/3
y = 3/3
y = 1
hope this help you
;) :)
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