Question

x+3y+2z=3, 4x+5y-3z=-3, 3x-2y+17z=42. solve by matrix inversion method​

Answer 1

Answer:

Given system of linear equations are 

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤⎣⎢⎢⎡xyz⎦⎥⎥⎤=⎣⎢⎢⎡5−43⎦⎥⎥⎤ which is in the form of AX=B

A=⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤

∣A∣=10+15+15=40=0

∴ A−1 exists

To find adjoint of A

A11=5