(x+3y) (3x-y) find the product
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(x+3y)(3x-y)
=x(3x-y)+3y(3x-y)
=3x²-xy+9xy-3y²
=3x²-3y²+6xy
Answered by
2
(x+3y)(3x-y)
=x*3x+x*(-y)+3x*3y+3y*(-y)
=3x^2-xy+9xy-3y^2
=3x^2+8xy-3y^2
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