Question

-x - 3y = 4 = x + 3y + 4 = 0, which is the required equation.
1
EXERCISE 20F
1. Find the equation of the line for which
(i) p = 3 and a = 45°
(ii) p = 5 and a = 135°
(iii) p = 8 and a = 150°
(iv) p = 3 and a = 225°
(v) p = 2 and a = 300°
(vi) p = 4 and a = 180°
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Answer 1

here ,x2+4x-3xy-12y=0

=x(x+4)-3y(x+4)0

or,(x+4)(x-3y)=0

=x+4=0 or x-3y=0

=x=-4 or x=3y

therefore,x=-4 or x=3y