x+3y+5z=22;5x-3y+2z=5
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Answered by
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hii frnd ..
solve the 3 equations u will get the values
hope u got it....
solve the 3 equations u will get the values
hope u got it....
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nayandeep:
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Answered by
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For three variable question there must be 3 equation - So 1st we must make it in 3 equation
x + 3y + 5z = 22 .............(1)
Multiply both side by 2,
2(x+ 3y+ 5z) = 22x2
2x+ 6y + 10z = 44...........(2)
5x -3y +2z = 5.............(3)
Multiply both side by 5,
5(5x -3y +2z) = 5x5
25x -15y +10z =25
or -25x +15y -10z = -25..............(4)
Using equation 2 &4, we get
2x +6y +10z -25x +15y -10z = 44-25
-23x +21y = 19..............(5)
Now subtracting equation 2&4, we get
25x -15y +10z +2x +6y -10z = 25+44
27x -9y = 69
9x -3y = 23 .............(6)
Now solve further and u can get answers
x + 3y + 5z = 22 .............(1)
Multiply both side by 2,
2(x+ 3y+ 5z) = 22x2
2x+ 6y + 10z = 44...........(2)
5x -3y +2z = 5.............(3)
Multiply both side by 5,
5(5x -3y +2z) = 5x5
25x -15y +10z =25
or -25x +15y -10z = -25..............(4)
Using equation 2 &4, we get
2x +6y +10z -25x +15y -10z = 44-25
-23x +21y = 19..............(5)
Now subtracting equation 2&4, we get
25x -15y +10z +2x +6y -10z = 25+44
27x -9y = 69
9x -3y = 23 .............(6)
Now solve further and u can get answers
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