Question

x+3y=6 , 2x-3y=12 ....Solve it in Cross Multiplication Method .
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Answer 1

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Answer 2

Given : $x+3y=6\ and\ 2x-3y=12$

To find : x= ? and y = ?

Solution :

Using the cross multiplication we get :

$x=\dfrac{b_1c_2-b_2c_1}{a_1b_2-a_2b_1}\\\\x=\dfrac{3\times -12-(-3)\times -6}{1\times -3-2\times 3}\\\\x=\dfrac{-36-18}{-3-6}\\\\x=\dfrac{54}{-9}\\\\x=-6$

Similarly,

$y=\dfrac{c_1a_2-a_1c_2}{a_1b_2-a_2b_1}\\\\y=\dfrac{-6\times 2-1\times -12}{1\times -3-2\times 3}\\\\y=\dfrac{-12+12}{-3-6}\\\\y=0$

Hence, the value of x = -6 and y = 0.