Question

x-3y=6 2x+3y=12 solve the linear equations by the substitution method​ please answer dont send irrespective answer​

Answer 1

Answer:

Value of:

• x = 6
• y = 0

Step-by-step explanation:

Equations are:

• x - 3y = 6 _____(i)
• 2x + 3y = 12 _____(ii)

To solve:

• Using the substitution method.

In equation (i).

⇢ x - 3y = 6

⇢ x = 6 + 3y

In equation (ii).

⇢ 2x + 3y = 12

Substituting x.

⇢ 2(6 + 3y) + 3y = 12

⇢ 12 + 6y + 3y = 12

⇢ 9y = 12 - 12

⇢ 9y = 0

⇢ y = 0/9

⇢ y = 0

In equation (i).

⇢ x - 3y = 6

Substituting y.

⇢ x - 3(0) = 6

⇢ x - 0 = 6

⇢ x = 6

Answer 2

Given :-

x - 3y = 6

2x + 3y = 12

To Find :-

Value of x and y

Solution :-

By using the first equation we get

$\sf x-3y=6$

$\sf x =3y+6$

Now

By putting the value of x

$\sf 2(3y+6) = 12$

$\sf 2(3y+6) + 3y = 12$

$\sf 6y + 12 + 3y = 12$

$\sf 9y +12=12$

$\sf 9y = 0$

$\sf y=0$

Now

By using 1

$\sf x- 3(0) = 6$

$\sf x-0=6$

$\sf x= 0 +6$

$\sf x=6$