Question

x -3y - 7 = 0,
3x -3y -15 =0,
by substitution method
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Answer 1

Answer:

x-3y-7=0

3x-3y-15=0

x-y-5=0

x-3y=7

(-) x-y =5

(+) (-)

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-2y=2

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y=2/-2

y= -1

substitute y= -1 in 2x-3y=7

2x-(-21)=7

2x+21=7

2x=28

x=28/2

x=14

Therefore x=14, y= -1