Question

X-3y-7=0 3x-3y-15=0 solve it by cross multiplication method

Answer 1

the value of x and y is 4 and -1 respectively

Answer 2

Answer:

x = 4 and y = 1

Step-by-step explanation:

Given : $x-3y-7=0 \\3x-3y-15=0$

To Find :  solve it by cross multiplication method

Solution:

Cross multiplication method

Equations : $a_1x+b_1x+c_1=0\\a_2x+b_2x+c_2=0$

$\frac{x}{b_1c_2-c_1b_2}=\frac{y}{a_1c_2-a_2c_1} =\frac{1}{a_1b_2-a_2b_1}$

Comparing the given equations

$x-3y-7=0 \\3x-3y-15=0$

$\frac{x}{(-3)(-15)-(-7)(-3)}=\frac{y}{(1)(-15)-(3)(-7)} =\frac{1}{(1)(-3)-(3)(-3)}$

$\frac{x}{24}=\frac{y}{6} =\frac{1}{6}$

$\frac{x}{4}=\frac{y}{1} =\frac{1}{1}$

So, x = 4 and y = 1