Question

x+3y/x+y=3/2 then find the value of x^3+y^3/x^3-y^3 solve by all dendo method like componendo-dividendo etc​

Answer 1

Answer:

Step-by-step explanation:

x+3y/x+y=3/2

x-3y=0

x=3y

putting value of x

x^3+y^3/x^3-y^3

27y^3+y^3/27y^3-y^3

28y^3/26y^3

=14/13

Answer 2

Answer:

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