Question

X+3y/x+y=3/2,then find value of x³+y³/x³-y³​

Answer 1

Step-by-step explanation:

x+3y/x+y=3/2

x+3y=3

x+y=2

-. -/

2y=2

y=1. x+y=2. x+1=2. x=1

${x3 + {y3 \div {x3 + - {y3}^{?} }^{?} }^{?} }^{?}$

1+1/1+1

2/2

=1