Question

x^4 - 14x^2 + 1 factorise​

Answer 1

Answer:

x⁴-14x²+1

x⁴+2x²+1-16x²

(x²+1) ²-(4x) ²

by using identity

a²-b²=(a+b) (a-b)

(x²+4x+1) (x²-4x+1)

Answer 2

Step-by-step explanation:

Factorise is nothing but writing the expression in the product of two different factors.

Factor: A term who can divide a specific expression or no. without leaving no. remainder.

${x}^{4} - 14 {x}^{2} + 1 \\ \\ {x}^{4} + 2 {x}^{2} + 1 - {16x}^{2} \\ \\ {(x {}^{2} + 1) }^{2} - 16 {x}^{2} \\ \\ {( {x}^{2} + 1) }^{2} - {(4x)}^{2} \\ \\ ( {x}^{2} + 1 + 4x)( {x}^{2} + 1 - 4x)$

Using Identity

a² + 2ab +b² = (a + b)²

a² - b² = (a+b)(a-b)