Question

(x+4)²-5xy+20y-6y




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Answer 1

Given,

$\begin{lgathered}= > {(x + 4)}^{2} - 5xy + 20y - 6y \\ = > {(x + 4)}^{2} - 5y(x + 4) - 6y \\ let \: x + 4be \: z. \\ then...... \\ = > {z}^{2} - 5yz - 6y \\ = > {z}^{2} - 6yz + yz - 6y \\ = > z(z - 6y) + z(z - 6y) \\ = > 2z(z - 6y) \\ = > 2(x + 4)(x + 4 - 6y) .\end{lgathered}$

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