Question

(x-4)(2x+3)=2x² find the value of x

Answer 1

Answer:

-12/5

Step-by-step explanation:

Given a quadratic equation such that,

$(x - 4)(2x + 3) = 2 {x}^{2}$

To find the value of x.

Solving the equation, we get,

$= > 2 {x}^{2} + 3x - 8x - 12 = 2 {x}^{2}$

Subtracting 2x^2 on both sides,

Therefore, we get,

$= > 2 {x}^{2} + 3x - 8x - 12 - 2 {x}^{2} = 2 {x}^{2} - 2 {x}^{2} \\ \\ = > 3x - 8x - 12 = 0 \\ \\ = > - 5x -1 2 = 0$

Adding 5x on both sides,

Therefore, we will get,

$= > - 5x - 12 + 5x = 5x \\ \\ = > 5x = - 12$

Dividing both the sides by 5,

Therefore, we will get,

$= > \frac{5x}{5} = - \frac{12}{5} \\ \\ = > x = - \frac{12}{5}$

Hence, the required value of x = -12/5.

Answer 2

${\sf{(x - 4)(2x + 3) = 2 {x}^{2}}} \\ \\⇢{\sf{2 {x}^{2} + 3x - 8x - 12 = 2 {x}^{2} }}\\ \\ ⇢{\sf{ {2x}^{2} - 5x - 12 = 2 {x}^{2} }} \\ \\⇢{\sf{ - 5x - 12 = {2x}^{2} - {2x}^{2}}}\\ \\⇢{\sf{ - 5x - 12 = 0}} \\ \\⇢{\sf{- 5x = 12}}\\ \\ ⇢{\sf{x = \frac{12}{ - 5}}}\\ \\⇢ \red{\sf{x = \frac{-12}{ 5}}}$