Math, asked by ghoshalshampa1, 8 months ago

(x-4)(2x+3)=2x² find the value of x

Answers

Answered by Anonymous
7

Answer:

-12/5

Step-by-step explanation:

Given a quadratic equation such that,

(x - 4)(2x + 3) = 2 {x}^{2}

To find the value of x.

Solving the equation, we get,

 =  > 2 {x}^{2}  + 3x - 8x - 12 = 2 {x}^{2}

Subtracting 2x^2 on both sides,

Therefore, we get,

 =  > 2 {x}^{2}  + 3x - 8x - 12 - 2 {x}^{2}  = 2 {x}^{2}   - 2 {x}^{2}   \\  \\  =  > 3x - 8x - 12 = 0 \\  \\  =  >  - 5x -1 2 = 0

Adding 5x on both sides,

Therefore, we will get,

 =  >  - 5x - 12 + 5x = 5x \\  \\  =  > 5x =  - 12

Dividing both the sides by 5,

Therefore, we will get,

 =  >  \frac{5x}{5}  =  -  \frac{12}{5}  \\  \\  =  > x =  -  \frac{12}{5}

Hence, the required value of x = -12/5.

Answered by Anonymous
7

{\sf{(x - 4)(2x  + 3) = 2 {x}^{2}}} \\ \\⇢{\sf{2 {x}^{2}  + 3x - 8x - 12 = 2 {x}^{2}  }}\\ \\ ⇢{\sf{ {2x}^{2}  - 5x - 12 = 2 {x}^{2} }} \\ \\⇢{\sf{ - 5x - 12 =  {2x}^{2}  -  {2x}^{2}}}\\  \\⇢{\sf{  - 5x - 12 = 0}} \\  \\⇢{\sf{- 5x = 12}}\\ \\ ⇢{\sf{x =  \frac{12}{ - 5}}}\\   \\⇢ \red{\sf{x = \frac{-12}{  5}}}

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